8x^2+x=5

Solution for 8x^2+x=5 equation:

8x^2+x=5

We move all terms to the left:

8x^2+x-(5)=0

a = 8; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·8·(-5)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{161}}{2*8}=\frac{-1-\sqrt{161}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{161}}{2*8}=\frac{-1+\sqrt{161}}{16}
$